Dartmouth Professor Discusses Foucault's Pendulum https://www.youtube.com/watch?v=aMxLVDuf4VY
Dear Professor Jim LaBelle,
Thanks for reading this email. I have watched your film about Foucault's Pendulum. At the north and south pole the phenomena results in a rotating pendulum. The rotation is 2 pi in 1 day which is 7.27e-5 rad/sec.
Particles that go into interation dictate their non-moveing system. Other particles that do not interfere with this interaction cannot dictate the non-moveing system because that would interfere with the interaction. So the particles of bob interact with the particles of the earth and a extra rotation w rad/sec is the result. We now have an extra parameter.
Forces which are second order differential equations cannot create this extra parameter. We need to construct a third order differential equation.
The described phenonema of a rotating pendulum could be described by a normal pendulum equation (1) and then stating the result should be rotating with w rad/sec.
But then the particles of the earth are dictating the non-moving system of the bob particles to be rotating because it is observed rotating.
And the particles of the earth are dictating the system to be non-rotating because equation 1 is a non-rotating equation.
The normal pendulum has no rotation.
If a rotating pendulum is observed then one should create a differential equation that has a rotating pendulum as the result on the computer.
Is this correct and logical? The picture is created by a third order differential equation. I have placed the email here.
What I like about the third order differential equation is that the rotation velocity is now one parameter. Just like acceleration, velocity and position are parameters in a second order differential equation. But there are a lot of things that need to be discussed now. The extra parameter gave an extra differentiation of space by time and resulted in reasoning in accelerations differentiated by time.
The Statement:
If a rotating pendulum is observed then one should create a differential equation that has a rotating pendulum as the result on the computer.
Is the reason for the reasoning in third order equations, this is science.
Thanks for any reaction in advance.
Regards ir.S.J.Boersen (Master in physics)
De pendulum van Foucault is een roterende slinger. De rotatie van de slinger komt voort uit de draaiing van de aarde om zijn as en komt ook voort uit de draaiing van de aarde rond de zon. De draaiing van het zonnestelsel in de melkweg heeft ook een kleine invloed. Als een roterende slinger is waargenomen is het wetenschappelijk een differentiaal vergelijking hiervoor op te schrijven. De vergelijkingen 1 tot en met 12 hebben het bovenstaande plaatje gemaakt.
The pendulum of Foucault (1819-1868) is a rotating pendulum. The rotation of the pendulum results from the rotation of the earth around its axis and also from the rotation of the earth around the sun. The rotation of the solar system in the galaxy also has a small influence. If a rotating pendulum is observed, it is scientifically to write down a differential equation for this. The equations 1 to 12 have made the above picture.
 
 
Some pictures out of my reasoning
Third order
Third order Third order Third order
stefanboersen@hotmail.com

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